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JAMB 2004 · UME · Q46

In how many ways can 2 students be selected from a group of 5 students in a debating competition?

Worked solution (try it first)
  1. The two students form a pair, so their order doesn't matter: use 5C2^5C_2.
  2. 5C2=5×42×1^5C_2 = \dfrac{5 \times 4}{2 \times 1}
    =10= 10 ways, option A.

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