JAMB 2004 · UME · Q7

Simplify 13+2\dfrac{1}{\sqrt3 + 2} in the form a+b3a + b\sqrt3.

Worked solution (try it first)
  1. Multiply the top and bottom by the conjugate of the bottom, 2−32 - \sqrt3.
  2. Bottom: (2+3)(2−3)=4−3(2 + \sqrt3)(2 - \sqrt3) = 4 - 3, which is 1.
  3. So the value is 2−32 - \sqrt3, option C.

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