JAMB 2010 · UTME · Q25

If ∣x327∣=15\begin{vmatrix} x & 3 \\ 2 & 7 \end{vmatrix} = 15, find the value of xx.

Worked solution (try it first)
  1. A 2×22 \times 2 determinant is ad−bcad - bc: 7x−3×2=7x−67x - 3 \times 2 = 7x - 6.
  2. So 7x−6=157x - 6 = 15.
  3. Add 6 to both sides: 7x=217x = 21.
  4. Divide by 7: x=3x = 3, option A.

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