Stepwise
Start practisingPractise

JAMB 2010 · UTME · Q4

A student measures a piece of rope and found that it was 1.26 m1.26\text{ m} long. If the actual length of the rope was 1.25 m1.25\text{ m}, what was the percentage error in the measurement?

Worked solution (try it first)
  1. The error is 1.26−1.25=0.011.26 - 1.25 = 0.01 m.
  2. Divide by the actual length and multiply by 100: 0.011.25×100%=11.25%\frac{0.01}{1.25} \times 100\% = \frac{1}{1.25}\%.
  3. 1÷1.25=0.81 \div 1.25 = 0.8, so the percentage error is 0.80%, option D.

Report a problem with this question