JAMB 2010 · UTME · Q48

Find the standard deviation of 2, 3, 5 and 6.

Worked solution (try it first)
  1. The mean is 2+3+5+64=4\frac{2 + 3 + 5 + 6}{4} = 4.
  2. The squared deviations are 4, 1, 1, 4, which add up to 10.
  3. The variance is 104=52\frac{10}{4} = \frac52, so the standard deviation is 52\sqrt{\frac52}, option A.

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