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JAMB 2010 · UTME · Q8

Given that log⁡2=0.3010\log 2 = 0.3010 and log⁡7=0.8451\log 7 = 0.8451, evaluate log⁡112\log 112.

Worked solution (try it first)
  1. Write 112 using 2 and 7: 112=16×7=24×7112 = 16 \times 7 = 2^4 \times 7.
  2. So log⁡112=4log⁡2+log⁡7\log 112 = 4\log 2 + \log 7.
  3. That is 4(0.3010)+0.8451=1.2040+0.84514(0.3010) + 0.8451 = 1.2040 + 0.8451
    =2.0491= 2.0491, option B.

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