JAMB 2012 · UTME · Q2✱

Convert 1126112_6 to a number in base three.

Worked solution (try it first)
  1. Change to base ten using place values: 1126=1×36+1×6+2=44112_6 = 1 \times 36 + 1 \times 6 + 2 = 44.
  2. Divide by 3 repeatedly: 44=3×14+244 = 3 \times 14 + 2, 14=3×4+214 = 3 \times 4 + 2, 4=3×1+14 = 3 \times 1 + 1, and 1=3×0+11 = 3 \times 0 + 1.
  3. Read the remainders from the bottom up: 112231122_3, option D.

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