JAMB 2012 · UTME · Q3

Simplify 223×112445\dfrac{2\frac23 \times 1\frac12}{4\frac45}.

Worked solution (try it first)
  1. Change the mixed numbers to improper fractions: 223=832\frac23 = \frac83, 112=321\frac12 = \frac32 and 445=2454\frac45 = \frac{24}{5}.
  2. Top: 83×32=4\frac83 \times \frac32 = 4.
  3. Divide by flipping: 4×524=20244 \times \frac{5}{24} = \frac{20}{24}
    =56= \frac56, option C.

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