JAMB 2012 · UTME · Q25

In the diagram, QR∥TUQR \parallel TU, ∠PQR=80∘\angle PQR = 80^\circ and ∠PSU=95∘\angle PSU = 95^\circ. Calculate ∠SUT\angle SUT.

80°95°xPQSRTU
Worked solution (try it first)
  1. Draw a line through SS parallel to QRQR and TUTU.
  2. By corresponding angles, SPSP makes 80∘80^\circ with it, the same as ∠PQR\angle PQR.
  3. ∠PSU=95∘\angle PSU = 95^\circ, so SUSU lies 95∘−80∘=15∘95^\circ - 80^\circ = 15^\circ beyond the parallel line.
  4. By alternate angles with TUTU, ∠SUT=15∘\angle SUT = 15^\circ, option A.

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