JAMB 2012 · UTME · Q26

The angles of a pentagon are xx, 2x2x, 3x3x, 4x4x and 5x5x. Find the value of xx.

Worked solution (try it first)
  1. The interior angles of a pentagon add up to (5−2)×180∘=540∘(5 - 2) \times 180^\circ = 540^\circ.
  2. So x+2x+3x+4x+5x=540x + 2x + 3x + 4x + 5x = 540, which is 15x=54015x = 540.
  3. Divide by 15: x=36∘x = 36^\circ, option D.

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