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JAMB 2013 · UTME · Q16

Solve 3(x+2)>6(x+3)3(x + 2) > 6(x + 3).

Worked solution (try it first)
  1. Expand both brackets: 3x+6>6x+183x + 6 > 6x + 18.
  2. Subtract 6x6x and 6 from both sides: −3x>12-3x > 12.
  3. Divide by −3-3 and reverse the sign: x<−4x < -4, option A.

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