JAMB 2014 · UTME · Q40

Find the minimum value of $y = x^2 - 2x - 3$ .

Worked solution (try it first)

At the minimum $\frac{dy}{dx} = 2x - 2 = 0$ , so $x = 1$ .
Put $x = 1$ into $y$ : $1 - 2 - 3 = -4$ .
So the minimum value is $-4$ , option A.

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