JAMB 2015 · UTME · Q11

A solid cylinder of radius 3 cm3\text{ cm} has a total surface area of 36π cm236\pi\text{ cm}^2. Find its height.

Worked solution (try it first)
  1. Total surface area of a solid cylinder: 2πr(r+h)=2π×3×(3+h)2\pi r(r + h) = 2\pi \times 3 \times (3 + h)
    =6π(3+h)= 6\pi(3 + h).
  2. Set it equal to 36π36\pi and divide both sides by 6π6\pi: 3+h=63 + h = 6.
  3. So h=3h = 3 cm, option B.

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