JAMB 2017 · UTME · Q12

PQRSTVPQRSTV is a regular hexagon of side 7 cm7\text{ cm} inscribed in a circle. Find the circumference of the circle. [Take π=227]\left[\text{Take }\pi = \frac{22}{7}\right]

Worked solution (try it first)
  1. A regular hexagon splits into six equilateral triangles from the centre, so the radius equals the side: r=7r = 7 cm.
  2. Circumference =2πr=2×227×7= 2\pi r = 2 \times \frac{22}{7} \times 7.
  3. So the circumference is 44 cm, option C.

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