JAMB 2017 · UTME (set 2) · Q3

If U={x:x is an integer and 1≤x≤20}U = \{x : x \text{ is an integer and } 1 \le x \le 20\}, E1={x:x is a multiple of 3}E_1 = \{x : x \text{ is a multiple of 3}\} and E2={x:x is a multiple of 4}E_2 = \{x : x \text{ is a multiple of 4}\}, and an integer is picked at random from UU, find the probability that it is not in E2E_2.

Worked solution (try it first)
  1. E2E_2, the multiples of 4 up to 20, is {4,8,12,16,20}\{4, 8, 12, 16, 20\}, which has 5 members.
  2. So P(in E2)=520P(\text{in } E_2) = \frac{5}{20}
    =14= \frac14.
  3. Not in E2E_2 is the complement: 1−14=341 - \frac14 = \frac34, option A.

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