JAMB 2017 · UTME (set 2) · Q4

The curved surface area of a cylinder 5 cm5\text{ cm} high is 110 cm2110\text{ cm}^2. Find the radius of its base. [π=227]\left[\pi = \frac{22}{7}\right]

Worked solution (try it first)
  1. Curved surface area of a cylinder is 2πrh2\pi rh: 2×227×r×5=1102 \times \frac{22}{7} \times r \times 5 = 110.
  2. That is 2207r=110\frac{220}{7}r = 110, so r=110×7220=3.5r = 110 \times \frac{7}{220} = 3.5 cm, option B.

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