JAMB 2017 · UTME (set 2) · Q7

If y=xsin⁡xy = x\sin x, find dydx\dfrac{dy}{dx} when x=π2x = \dfrac{\pi}{2}.

Worked solution (try it first)
  1. Product rule: dydx=sin⁡x+xcos⁡x\frac{dy}{dx} = \sin x + x\cos x.
  2. At x=π2x = \frac\pi2, sin⁡x=1\sin x = 1 and cos⁡x=0\cos x = 0, so dydx=1+0=1\frac{dy}{dx} = 1 + 0 = 1, option C.

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