NECO 2022 · Paper 1 · Q31

Expressions, formulae & change of subject

Given that $V = \frac{1}{3}\pi r^2 (2r + h)$ , make $h$ the subject of the formula.

Worked solution (try it first)

Multiply both sides by 3: $3V = \pi r^2 (2r + h)$ .
Divide both sides by $\pi r^2$ : $\dfrac{3V}{\pi r^2} = 2r + h$ .
Subtract $2r$ : $h = \dfrac{3V}{\pi r^2} - 2r$ , option B.

Report a problem with this question