NECO 2022 · Paper 1 · Q32

Variation

$A$ varies inversely as the square of $B$ and $B$ varies directly as the square of $C$ . Find the equation connecting $A$ and $C$ , where $K$ is a constant.

Worked solution (try it first)

Write the two variations: $A = \dfrac{k}{B^2}$ and $B = mC^2$ .
Square the second: $B^2 = m^2 C^4$ .
Substitute: $A = \dfrac{k}{m^2 C^4}$ .
Call $\frac{k}{m^2} = K$ , so $A = \dfrac{K}{C^4}$ , option D.

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