NECO 2022 · Paper 1 · Q33

If MM varies inversely as NN and M=152M = \frac{15}{2} when N=4N = 4, find the value of NN when M=(120)−1M = \left(\frac{1}{20}\right)^{-1}.

Worked solution (try it first)
  1. Write M=kNM = \dfrac{k}{N}, so k=MN=152×4=30k = MN = \frac{15}{2} \times 4 = 30.
  2. A power of −1-1 turns the fraction upside down: M=(120)−1=20M = \left(\frac{1}{20}\right)^{-1} = 20.
  3. So N=kMN = \dfrac{k}{M}
    =3020= \dfrac{30}{20}
    =112= 1\frac{1}{2}, option C.

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