NECO 2023 · Paper 1 · Q59

If y=3x2−4x−12y = 3x^2 - 4x - 12, find the value of xx when dydx=0\dfrac{dy}{dx} = 0.

Worked solution (try it first)
  1. Differentiate: dydx=6x−4\frac{dy}{dx} = 6x - 4.
  2. Set it to zero: 6x=46x = 4, so x=46=23x = \frac46 = \frac23, option C.

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