NECO 2024 · Paper 1 · Q23

Quadratics & their graphs

The product of two numbers is 40 and their sum is 13. Find the numbers.

Worked solution (try it first)

Call the numbers $x$ and $13 - x$ , so their sum is 13.
Their product is $x(13 - x) = 40$ .
Rearrange: $x^2 - 13x + 40 = 0$ , which factorises as $(x - 5)(x - 8) = 0$ .
So the numbers are 5 and 8, option E.

Report a problem with this question