WAEC 2013 · Paper 2 · Q1

  1. (a)

    If the coefficients of x2x^2 and x3x^3 in the expansion of (p+qx)7(p + qx)^7 are equal, express qq in terms of pp.

  2. (b)

    A man makes a weekly contribution into a fund. In the first week, he paid ₦180.00, the second week ₦260.00, the third week ₦340.00 and so on. How much would he have contributed in 16 weeks?

Worked solution (try it first)

(a)

  1. The x2x^2 term of (p+qx)7(p + qx)^7 is (72)p5(qx)2=21p5q2x2\binom72p^5(qx)^2 = 21p^5q^2x^2.
  2. The x3x^3 term is (73)p4(qx)3=35p4q3x3\binom73p^4(qx)^3 = 35p^4q^3x^3.
  3. Set the coefficients equal: 21p5q2=35p4q321p^5q^2 = 35p^4q^3.
  4. Divide both sides by 7p4q27p^4q^2: 3p=5q3p = 5q, so q=35pq = \frac35p.

(b)

  1. The payments form an A.P. with a=180a = 180 and d=80d = 80.
  2. The total in 16 weeks is S16S_{16}.
  3. S16=162[2(180)+15(80)]S_{16} = \dfrac{16}{2}[2(180) + 15(80)]
    =8(360+1200)= 8(360 + 1200)
    =8×1560= 8 \times 1560.
  4. So he contributes ₦12 480.

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