WAEC 2016 · Paper 2 · Q14

Four vectors, r=αi+βj\mathbf r = \alpha\mathbf i + \beta\mathbf j where α\alpha and β\beta are positive constants, s=2i−j\mathbf s = 2\mathbf i - \mathbf j, m=3i+2j\mathbf m = 3\mathbf i + 2\mathbf j and n=i+j\mathbf n = \mathbf i + \mathbf j, are such that the magnitude of r\mathbf r is three times that of s\mathbf s and r\mathbf r is parallel to (m−n)(\mathbf m - \mathbf n).

  1. (a)

    Find the values of α\alpha and β\beta.

    Separate values with commas, e.g. 3, −2

  2. (b)

    Calculate the magnitude and direction (bearing) of (r−s)(\mathbf r - \mathbf s).

    Separate values with commas, e.g. 3, −2

Worked solution (try it first)

(a)

  1. m−n=2i+j\mathbf m - \mathbf n = 2\mathbf i + \mathbf j, so r=k(2i+j)\mathbf r = k(2\mathbf i + \mathbf j) for some k>0k > 0 (the parts are positive).
  2. ∣s∣=4+1=5|\mathbf s| = \sqrt{4 + 1} = \sqrt5, so ∣r∣=35|\mathbf r| = 3\sqrt5.
  3. ∣r∣=k5=35|\mathbf r| = k\sqrt5 = 3\sqrt5, so k=3k = 3: α=6\alpha = 6 and β=3\beta = 3.

(b)

  1. r−s=(6−2)i+(3+1)j\mathbf r - \mathbf s = (6 - 2)\mathbf i + (3 + 1)\mathbf j
    =4i+4j= 4\mathbf i + 4\mathbf j.
  2. Its magnitude is 32=42≈5.66\sqrt{32} = 4\sqrt2 \approx 5.66.
  3. Equal east and north parts: the bearing is 045∘045^\circ.

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