WAEC 2016 · Paper 2 · Q2

  1. (a)

    Given that (5,2)(5, 2), (−4,k)(-4, k) and (2,1)(2, 1) lie on a straight line, find the value of kk.

Worked solution (try it first)
  1. On one line, the gradients between pairs of points are equal.
  2. From (2,1)(2, 1) to (5,2)(5, 2): 2−15−2=13\dfrac{2 - 1}{5 - 2} = \dfrac13.
  3. From (−4,k)(-4, k) to (5,2)(5, 2): 2−k5+4=13\dfrac{2 - k}{5 + 4} = \dfrac13, so 2−k=32 - k = 3 and k=−1k = -1.

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