WAEC 2019 · Paper 2 · Q7Vectors(a)Find the angle between OP→=(−3−4)\overrightarrow{OP} = \begin{pmatrix} -3 \\ -4 \end{pmatrix}OP=(−3−4) and OQ→=(8−15)\overrightarrow{OQ} = \begin{pmatrix} 8 \\ -15 \end{pmatrix}OQ=(8−15).CheckWorked solution (try it first)OP→⋅OQ→=(−3)(8)+(−4)(−15)\overrightarrow{OP} \cdot \overrightarrow{OQ} = (-3)(8) + (-4)(-15)OP⋅OQ=(−3)(8)+(−4)(−15)=−24+60= -24 + 60=−24+60=36= 36=36.∣OP→∣=5|\overrightarrow{OP}| = 5∣OP∣=5 and ∣OQ→∣=64+225|\overrightarrow{OQ}| = \sqrt{64 + 225}∣OQ∣=64+225=17= 17=17.cosθ=3685\cos\theta = \dfrac{36}{85}cosθ=8536≈0.4235\approx 0.4235≈0.4235, so θ≈64.94∘\theta \approx 64.94^\circθ≈64.94∘.Report a problem with this question