WAEC 2019 · Paper 2 · Q7

  1. (a)

    Find the angle between OP→=(−3−4)\overrightarrow{OP} = \begin{pmatrix} -3 \\ -4 \end{pmatrix} and OQ→=(8−15)\overrightarrow{OQ} = \begin{pmatrix} 8 \\ -15 \end{pmatrix}.

Worked solution (try it first)
  1. OP→⋅OQ→=(−3)(8)+(−4)(−15)\overrightarrow{OP} \cdot \overrightarrow{OQ} = (-3)(8) + (-4)(-15)
    =−24+60= -24 + 60
    =36= 36.
  2. ∣OP→∣=5|\overrightarrow{OP}| = 5 and ∣OQ→∣=64+225|\overrightarrow{OQ}| = \sqrt{64 + 225}
    =17= 17.
  3. cos⁡θ=3685\cos\theta = \dfrac{36}{85}
    ≈0.4235\approx 0.4235, so θ≈64.94∘\theta \approx 64.94^\circ.

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