Past papers › WAEC · 2019 · Private · Further Maths · Paper 2 › Question 8 Question WAEC Further Maths 2019 Theory Statics: forces, equilibrium & moments Statics: forces, equilibrium & moments
In the diagram, a mass of 12 kg 12\text{ kg} 12 kg R R R 45 ∘ 45^\circ 4 5 ∘ [ Take g = 10 m s − 2 ] [\text{Take } g = 10\text{ m s}^{-2}] [ Take g = 10 m s − 2 ]
(a) (b) Worked solution (try it first) The weight is
12 × 10 = 120 N 12 \times 10 = 120\text{ N} 12 × 10 = 120 N .
The string is at
45 ∘ 45^\circ 4 5 ∘ to the vertical.
(a) Up:
T cos 45 ∘ = 120 T\cos45^\circ = 120 T cos 4 5 ∘ = 120 , so
T = 120 2 ≈ 169.71 N T = 120\sqrt2 \approx 169.71\text{ N} T = 120 2 ≈ 169.71 N .
(b) Across:
R = T sin 45 ∘ = 120 N R = T\sin45^\circ = 120\text{ N} R = T sin 4 5 ∘ = 120 N .
Watch out
The angle is from the vertical, so the upward part of T T T Report a problem with this question