WAEC 2022 · Paper 1 · Q11

If (2−314)(−6k)=(3−26)\begin{pmatrix} 2 & -3 \\ 1 & 4 \end{pmatrix}\begin{pmatrix} -6 \\ k \end{pmatrix} = \begin{pmatrix} 3 \\ -26 \end{pmatrix}, find the value of kk.

Worked solution (try it first)
  1. Multiply the first row by the column: 2(−6)+(−3)k=32(-6) + (-3)k = 3, so −12−3k=3-12 - 3k = 3.
  2. Add 12 to both sides: −3k=15-3k = 15, so k=−5k = -5.
  3. Check with the second row: 1(−6)+4(−5)=−261(-6) + 4(-5) = -26.
  4. So k=−5k = -5, option B.

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