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WAEC 2022 · Paper 1 · Q13

Evaluate: 4P2+4C2−4P3^{4}P_2 + {^{4}C_2} - {^{4}P_3}.

Worked solution (try it first)
  1. 4P2=4×3=12^{4}P_2 = 4 \times 3 = 12 and 4P3=4×3×2=24^{4}P_3 = 4 \times 3 \times 2 = 24.
  2. For 4C2^{4}C_2, divide 4×34 \times 3 by 2×12 \times 1: 4C2=6^{4}C_2 = 6.
  3. So the value is 12+6−24=−612 + 6 - 24 = -6, option C.

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