WAEC 2022 · Paper 1 · Q31

Find the range of values of xx for which 2x2+7x−15≥02x^2 + 7x - 15 \ge 0.

Worked solution (try it first)
  1. Factorise: 2x2+7x−15=(2x−3)(x+5)2x^2 + 7x - 15 = (2x - 3)(x + 5), which is zero at x=32x = \frac32 and x=−5x = -5.
  2. The x2x^2 coefficient is positive, so the curve is U-shaped and is above zero outside the roots.
  3. So x≤−5x \le -5 or x≥32x \ge \frac32, option B.

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