WAEC 2022 · Paper 1 · Q34

The gradient of a function at any point (x,y)(x, y) is 2x−62x - 6. If the function passes through (1,2)(1, 2), find the function.

Worked solution (try it first)
  1. Integrate the gradient: y=∫(2x−6) dxy = \displaystyle\int (2x - 6)\,dx
    =x2−6x+c= x^2 - 6x + c.
  2. The curve passes through (1,2)(1, 2): 2=1−6+c2 = 1 - 6 + c, so 2=−5+c2 = -5 + c.
  3. Add 5 to both sides: c=7c = 7, so y=x2−6x+7y = x^2 - 6x + 7, option D.

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