A particle of mass 3 kg moving along a straight line under the action of a force F N covers a distance, d, at time, t, such that d=t2+3t. Find the magnitude of F at time t.
Worked solution (try it first)
Differentiate for the velocity: v=dtdd=2t+3.
Differentiate again for the acceleration: a=dtdv=2 m s−2.