WAEC 2022 · Paper 1 · Q35

A particle of mass 3 kg moving along a straight line under the action of a force FF N covers a distance, dd, at time, tt, such that d=t2+3td = t^2 + 3t. Find the magnitude of FF at time tt.

Worked solution (try it first)
  1. Differentiate for the velocity: v=dddt=2t+3v = \dfrac{dd}{dt} = 2t + 3.
  2. Differentiate again for the acceleration: a=dvdt=2 m s−2a = \dfrac{dv}{dt} = 2\text{ m s}^{-2}.
  3. By Newton's second law, F=ma=3×2=6F = ma = 3 \times 2 = 6 N, option D.

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