WAEC 2022 · Paper 1 · Q39

If f(x−1)=x3+3x2+4x−5f(x - 1) = x^3 + 3x^2 + 4x - 5, find f(2)f(2).

Worked solution (try it first)
  1. f(2)f(2) needs x−1=2x - 1 = 2, so x=3x = 3.
  2. Put x=3x = 3 into the right side: 27+27+12−527 + 27 + 12 - 5.
  3. So f(2)=61f(2) = 61, option A.

Report a problem with this question