WAEC 2008 · Paper 2 · Q5

  1. (a)

    A rectangular field is ll metres long and bb metres wide. Its perimeter is 280280 metres. If the length is two and a half times its breadth, find the values of ll and bb.

    Separate values with commas, e.g. 3, −2

  2. (b)

    The base of a pyramid is a 4.5 m4.5\text{ m} by 2.5 m2.5\text{ m} rectangle. The height of the pyramid is 4 m4\text{ m}. Calculate its volume.

Worked solution (try it first)

(a)

  1. The perimeter of a rectangle is 2(l+b)2(l + b), so 2(l+b)=2802(l + b) = 280 and l+b=140l + b = 140.
  2. The length is two and a half times the breadth: l=2.5bl = 2.5b.
  3. Substitute: 2.5b+b=1402.5b + b = 140, so 3.5b=1403.5b = 140 and b=40b = 40.
  4. Then l=2.5×40=100l = 2.5 \times 40 = 100.
  5. The field is 100 m100\text{ m} long and 40 m40\text{ m} wide.

(b)

  1. The volume of a pyramid is 13×base area×height\frac13 \times \text{base area} \times \text{height}.
  2. The base area is 4.5×2.5=11.25 m24.5 \times 2.5 = 11.25\text{ m}^2.
  3. V=13×11.25×4=15V = \frac13 \times 11.25 \times 4 = 15.
  4. The volume is 15 m315\text{ m}^3.

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