WAEC 2008 · Paper 2 · Q11

  1. (a)

    Using a ruler and a pair of compasses only, construct a quadrilateral PQRSPQRS in which ∣QR∣=6 cm|QR| = 6\text{ cm}, ∠PQR=90∘\angle PQR = 90^\circ, ∠QRS=120∘\angle QRS = 120^\circ, ∣RS∣=8 cm|RS| = 8\text{ cm} and ∣PQ∣=∣PS∣|PQ| = |PS|.

    Model answer
    6 cm8 cm120°PQRS

    Draw QR=6 cmQR = 6\text{ cm}. Construct 90∘90^\circ at QQ and 120∘120^\circ at RR (on the same side), and mark SS with RS=8 cmRS = 8\text{ cm}. Join QSQS and construct its perpendicular bisector; PP is where it cuts the perpendicular at QQ. Join PSPS.

  2. (b)

    Measure ∣PQ∣|PQ|.

Worked solution (try it first)

(a)

  1. Draw QR=6 cmQR = 6\text{ cm}.
  2. At QQ, construct 90∘90^\circ (bisect a straight angle).
  3. At RR, construct 120∘120^\circ (60∘60^\circ twice) on the same side as the 90∘90^\circ arm.
  4. Mark SS on the 120∘120^\circ arm with RS=8 cmRS = 8\text{ cm}.
  5. ∣PQ∣=∣PS∣|PQ| = |PS| means PP is equidistant from QQ and SS, so PP lies on the perpendicular bisector of QSQS.
  6. Join QSQS and construct its perpendicular bisector.
  7. PP is where this bisector cuts the 90∘90^\circ arm at QQ.
  8. Join PSPS to complete PQRSPQRS.

(b)

  1. Measure PQPQ: it is about 10.7 cm10.7\text{ cm}.

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