The first term of an Arithmetic Progression (A.P.) is −8. If the ratio of the 7th term to the 9th term is 5:8, find the common difference of the A.P.
(b)
A trader bought 30 baskets of pawpaw and 100 baskets of mangoes for ₦2,450.00. She sold the pawpaw at a profit of 40% and the mangoes at a profit of 30%. If her profit on the entire transaction was ₦855.00, find the: (i) cost price of a basket of pawpaw; (ii) selling price of the 100 baskets of mangoes.
Worked solution (try it first)
(a)
The nth term of an A.P. is a+(n−1)d.
With a=−8: the 7th term is −8+6d and the 9th term is −8+8d.
Their ratio is 5:8: −8+8d−8+6d=85.
Cross-multiply: 8(−8+6d)=5(−8+8d).
So −64+48d=−40+40d, 8d=24 and d=3.
(b)
Let a basket of pawpaw cost ₦p and a basket of mangoes cost ₦m.
Total cost: 30p+100m=2450 (1).
Profit on pawpaw is 40% of 30p and on mangoes 30% of 100m: 0.4×30p+0.3×100m=855, which is 12p+30m=855 (2).
Multiply (1) by 0.3: 9p+30m=735 (3).
Take (3) from (2): 3p=120, so p=40.
(i)
A basket of pawpaw cost ₦40.00.
(ii)
From (1), 100m=2450−1200=1250, so the mangoes cost ₦1,250.00.