WAEC 2016 · Paper 2 · Q2

  1. (a)

    Solve: 7(x+4)−23(x−6)≤2[x−3(x+5)]7(x + 4) - \frac23(x - 6) \le 2[x - 3(x + 5)].

    Show the answer

    x≤−6x \le -6

  2. (b)

    A transport company has a total of 20 vehicles made up of tricycles and taxicabs. Each tricycle carries 2 passengers while each taxicab carries 4 passengers. If the 20 vehicles carry a total of 66 passengers at a time, how many tricycles does the company have?

Worked solution (try it first)

(a)

  1. Simplify the right side first: 2[x−3(x+5)]=2[x−3x−15]2[x - 3(x + 5)] = 2[x - 3x - 15]
    =2(−2x−15)= 2(-2x - 15)
    =−4x−30= -4x - 30.
  2. Multiply every term by 3 to clear the fraction: 21(x+4)−2(x−6)≤3(−4x−30)21(x + 4) - 2(x - 6) \le 3(-4x - 30).
  3. Expand: 21x+84−2x+12≤−12x−9021x + 84 - 2x + 12 \le -12x - 90.
  4. So 19x+96≤−12x−9019x + 96 \le -12x - 90.
  5. Collect terms: 31x≤−18631x \le -186.
  6. Divide by 31 (positive, so the sign stays the same): x≤−6x \le -6.

(b)

  1. Let there be tt tricycles, so there are 20−t20 - t taxicabs.
  2. Passengers: 2t+4(20−t)=662t + 4(20 - t) = 66.
  3. So 2t+80−4t=662t + 80 - 4t = 66, −2t=−14-2t = -14 and t=7t = 7.
  4. The company has 7 tricycles.
  5. Check: 7 tricycles carry 14 and 13 taxicabs carry 52, making 66 ✓.

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