WAEC 2016 · Paper 2 · Q4

  1. (a)

    Solve the inequality 23(1−4x)−12(5−3x)≤14(7+9x)−13\frac23(1 - 4x) - \frac12(5 - 3x) \le \frac14(7 + 9x) - \frac13.

    Show the answer

    x≥−3941x \ge -\frac{39}{41}

  2. (b)

    A man standing 3 m3\text{ m} away from a tree observed that the angle of elevation of the top of the tree and the angle of depression of the bottom of the tree are 65∘65^\circ and 20∘20^\circ respectively. Find, correct to 3 significant figures, the height of the tree.

Worked solution (try it first)

(a)

  1. Multiply every term by 12: 8(1−4x)−6(5−3x)≤3(7+9x)−48(1 - 4x) - 6(5 - 3x) \le 3(7 + 9x) - 4.
  2. Expand: 8−32x−30+18x≤21+27x−48 - 32x - 30 + 18x \le 21 + 27x - 4.
  3. So −22−14x≤17+27x-22 - 14x \le 17 + 27x.
  4. Collect terms: −39≤41x-39 \le 41x, so x≥−3941x \ge -\frac{39}{41}.

(b)

  1. The man's eye is level with some point on the tree.
  2. Up from his eye level to the top: 3tan⁡65∘≈6.4343\tan 65^\circ \approx 6.434 m.
  3. Down from his eye level to the bottom: 3tan⁡20∘≈1.0923\tan 20^\circ \approx 1.092 m.
  4. The tree's height is the sum: 6.434+1.092≈7.53 m6.434 + 1.092 \approx 7.53\text{ m}.

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