WAEC 2018 · Paper 2 · Q5

  1. (a)

    Find the range of values of xx which satisfy the following inequalities simultaneously: 5−x>15 - x > 1 and 9+x≥89 + x \ge 8.

    Show the answer

    −1≤x<4-1 \le x < 4

  2. (b)

    In the diagram, OO is the centre of the circle PQRSPQRS, PSPS is a diameter, ∣PQ∣=∣QR∣|PQ| = |QR| and ∠PSR=56∘\angle PSR = 56^\circ. Find ∠QRS\angle QRS.

    56°OPQRS
Worked solution (try it first)

(a)

  1. First inequality: 5−x>15 - x > 1, so 4>x4 > x, that is x<4x < 4.
  2. Second: 9+x≥89 + x \ge 8, so x≥−1x \ge -1.
  3. Both at once: xx is at least −1-1 and less than 4, so −1≤x<4-1 \le x < 4.

(b)

  1. PQRSPQRS is a cyclic quadrilateral, so opposite angles add up to 180∘180^\circ: ∠PQR=180∘−56∘\angle PQR = 180^\circ - 56^\circ
    =124∘= 124^\circ.
  2. ∣PQ∣=∣QR∣|PQ| = |QR|, so triangle PQRPQR is isosceles: ∠QRP=180∘−124∘2\angle QRP = \frac{180^\circ - 124^\circ}{2}
    =28∘= 28^\circ.
  3. PSPS is a diameter, so ∠PRS=90∘\angle PRS = 90^\circ (angle in a semicircle).
  4. Then ∠QRS=∠QRP+∠PRS\angle QRS = \angle QRP + \angle PRS
    =28∘+90∘= 28^\circ + 90^\circ
    =118∘= 118^\circ.

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