WAEC 2019 · Paper 1 · Q16

If 3p=4q3p = 4q and 9p=8q−129p = 8q - 12, find the value of pqpq.

Worked solution (try it first)
  1. From 3p=4q3p = 4q, divide by 4: q=3p4q = \frac{3p}{4}, so 8q=6p8q = 6p.
  2. Substitute into the second equation: 9p=6p−129p = 6p - 12, so 3p=−123p = -12 and p=−4p = -4.
  3. Then q=3×(−4)4=−3q = \frac{3 \times (-4)}{4} = -3.
  4. So pq=(−4)(−3)=12pq = (-4)(-3) = 12, option A.

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