Past papers › WAEC · 2019 · May/June · General Maths · Paper 1 › Question 19 Question WAEC General Maths 2019 Objective Expressions, formulae & change of subject Quadratics & their graphs Expressions, formulae & change of subject, Quadratics & their graphs
WAEC 2019 · Paper 1 · Q19 Simplify x 2 − 5 x − 14 x 2 − 9 x + 14 \dfrac{x^2 - 5x - 14}{x^2 - 9x + 14} x 2 − 9 x + 14 x 2 − 5 x − 14 .
A x − 7 x + 7 \dfrac{x - 7}{x + 7} x + 7 x − 7 B x + 7 x − 7 \dfrac{x + 7}{x - 7} x − 7 x + 7 C x − 2 x + 4 \dfrac{x - 2}{x + 4} x + 4 x − 2 D x + 2 x − 2 \dfrac{x + 2}{x - 2} x − 2 x + 2
Worked solution (try it first) Top: two numbers multiplying to
− 14 -14 − 14 and adding to
− 5 -5 − 5 are
− 7 -7 − 7 and
2 2 2 , so
x 2 − 5 x − 14 = ( x − 7 ) ( x + 2 ) x^2 - 5x - 14 = (x - 7)(x + 2) x 2 − 5 x − 14 = ( x − 7 ) ( x + 2 ) .
Bottom:
− 7 -7 − 7 and
− 2 -2 − 2 multiply to 14 and add to
− 9 -9 − 9 , so
x 2 − 9 x + 14 = ( x − 7 ) ( x − 2 ) x^2 - 9x + 14 = (x - 7)(x - 2) x 2 − 9 x + 14 = ( x − 7 ) ( x − 2 ) .
Cancel
x − 7 x - 7 x − 7 :
x + 2 x − 2 \dfrac{x + 2}{x - 2} x − 2 x + 2 , option D.
Watch out
Check each factor pair adds to the middle number. For the top, + 7 +7 + 7 and − 2 -2 − 2 add to + 5 +5 + 5 , not − 5 -5 − 5 ; that pairing leads to options A and B with x + 7 x + 7 x + 7 . Report a problem with this question