WAEC 2019 · Paper 1 · Q24LogarithmsIf logx2=0.3\log_x 2 = 0.3logx2=0.3, evaluate logx8\log_x 8logx8.A2.4B1.2C0.9D0.6Worked solution (try it first)8=238 = 2^38=23, so logx8=3logx2\log_x 8 = 3\log_x 2logx8=3logx2.3×0.3=0.93 \times 0.3 = 0.93×0.3=0.9, option C.Report a problem with this question