WAEC 2019 · Paper 1 · Q26

Make bb the subject of the relation lb=12(a+b)hlb = \frac12(a + b)h.

Worked solution (try it first)
  1. Multiply by 2 and expand: 2lb=ah+bh2lb = ah + bh.
  2. Collect the bb terms: 2lb−bh=ah2lb - bh = ah, so b(2l−h)=ahb(2l - h) = ah.
  3. Divide by 2l−h2l - h: b=ah2l−hb = \dfrac{ah}{2l - h}, option A.

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