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WAEC 2019 · Paper 1 · Q34

Find the equation of a straight line passing through the point (1,−5)(1, -5) and having gradient 34\frac34.

Worked solution (try it first)
  1. Use y−y1=m(x−x1)y - y_1 = m(x - x_1) with (1,−5)(1, -5): y+5=34(x−1)y + 5 = \frac34(x - 1).
  2. Multiply both sides by 4: 4y+20=3x−34y + 20 = 3x - 3.
  3. Collect terms on one side: 3x−4y−23=03x - 4y - 23 = 0, option D.

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