WAEC 2020 · Paper 1 · Q19

In the diagram, PQ∥SRPQ \parallel SR. Find the value of xx.

x68°246°PQSR
Worked solution (try it first)
  1. Angles at a point: the angle between the two lines at the bend is 360∘−246∘=114∘360^\circ - 246^\circ = 114^\circ.
  2. Draw a line through the bend parallel to PQPQ.
  3. By alternate angles, the upper line makes xx with it and the lower line makes 68∘68^\circ with it.
  4. So x+68∘=114∘x + 68^\circ = 114^\circ, which gives x=46x = 46, option B.

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