WAEC 2020 · Paper 1 · Q20

Coordinate geometry

Find the equation of the line parallel to $2y = 3(x - 2)$ which passes through the point $(2, 3)$ .

Worked solution (try it first)

$2y = 3(x - 2)$ gives $y = \frac32x - 3$ , so its gradient is $\frac32$ .
Parallel lines have the same gradient.
Through $(2, 3)$ : $y - 3 = \frac32(x - 2)$ , so $y - 3 = \frac32x - 3$ .
Add 3 to both sides: $y = \frac32x$ , option C.

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