WAEC 2020 · Paper 1 · Q21

The expression 5x+36x(x+1)\dfrac{5x + 3}{6x(x + 1)} will be undefined when xx equals

Worked solution (try it first)
  1. The expression is undefined when the bottom 6x(x+1)6x(x + 1) is zero.
  2. 6x=06x = 0 gives x=0x = 0, and x+1=0x + 1 = 0 gives x=−1x = -1.
  3. So x∈{0,−1}x \in \{0, -1\}, option B.

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