WAEC 2020 · Paper 1 · Q24

In the diagram, XYZXYZ is an equilateral triangle of side 6 cm6\text{ cm} and TT is the midpoint of XYXY. Find tan⁡(∠XZT)\tan(\angle XZT).

XYZT
Worked solution (try it first)
  1. Every angle of an equilateral triangle is 60∘60^\circ, so ∠XZY=60∘\angle XZY = 60^\circ.
  2. ZTZT goes from ZZ to the midpoint of XYXY, so it is a line of symmetry and cuts the angle at ZZ in half: ∠XZT=30∘\angle XZT = 30^\circ.
  3. So tan⁡(∠XZT)=tan⁡30∘\tan(\angle XZT) = \tan30^\circ
    =13= \frac{1}{\sqrt3}, option A.

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