WAEC 2020 · Paper 1 · Q33

In the diagram, OO is the centre of the circle and RPRP is a diameter. If ∠OPQ=48∘\angle OPQ = 48^\circ, find the value of mm.

m48°ORPQ
Worked solution (try it first)
  1. OP=OQOP = OQ (radii), so triangle OPQOPQ is isosceles and ∠OQP=∠OPQ=48∘\angle OQP = \angle OPQ = 48^\circ.
  2. ROPROP is a straight line, so m=∠ROQm = \angle ROQ is an exterior angle of triangle OPQOPQ.
  3. An exterior angle equals the sum of the two interior opposite angles: m=48∘+48∘=96∘m = 48^\circ + 48^\circ = 96^\circ, option A.

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