WAEC 2020 · Paper 1 · Q38

Solid mensuration

The diameter of a sphere is $12\text{ cm}$ . Calculate, correct to the nearest $\text{cm}^3$ , the volume of the sphere. $\left[\text{Take }\pi = \frac{22}{7}\right]$

Worked solution (try it first)

Radius $= 12 \div 2 = 6$ cm, so $r^3 = 216$ .
Volume: $\frac43 \times \frac{22}{7} \times 216 \approx 905.14\text{ cm}^3$ .
To the nearest cm³, $905\text{ cm}^3$ , option C.

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